Integrand size = 31, antiderivative size = 133 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {d^3 \text {arctanh}(\sin (e+f x))}{a^3 f}+\frac {(c-d) (c+d \sec (e+f x))^2 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {(c-d) \left (2 \left (2 c^2+8 c d+11 d^2\right )+\left (2 c^2+11 c d+29 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2} \]
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Time = 0.24 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.45, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.194, Rules used = {4072, 100, 150, 65, 223, 209} \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {2 d^3 \tan (e+f x) \arctan \left (\frac {\sqrt {a-a \sec (e+f x)}}{\sqrt {a (\sec (e+f x)+1)}}\right )}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a \sec (e+f x)+a}}+\frac {(c-d) \tan (e+f x) \left (\left (2 c^2+11 c d+29 d^2\right ) \sec (e+f x)+2 \left (2 c^2+8 c d+11 d^2\right )\right )}{15 a f (a \sec (e+f x)+a)^2}+\frac {(c-d) \tan (e+f x) (c+d \sec (e+f x))^2}{5 f (a \sec (e+f x)+a)^3} \]
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Rule 65
Rule 100
Rule 150
Rule 209
Rule 223
Rule 4072
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a^2 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {(c+d x)^3}{\sqrt {a-a x} (a+a x)^{7/2}} \, dx,x,\sec (e+f x)\right )}{f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (c+d \sec (e+f x))^2 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {\tan (e+f x) \text {Subst}\left (\int \frac {(c+d x) \left (-a^2 \left (2 c^2+5 c d-2 d^2\right )-5 a^2 d^2 x\right )}{\sqrt {a-a x} (a+a x)^{5/2}} \, dx,x,\sec (e+f x)\right )}{5 a f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (c+d \sec (e+f x))^2 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {(c-d) \left (2 \left (2 c^2+8 c d+11 d^2\right )+\left (2 c^2+11 c d+29 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}-\frac {\left (d^3 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-a x} \sqrt {a+a x}} \, dx,x,\sec (e+f x)\right )}{a f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (c+d \sec (e+f x))^2 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {(c-d) \left (2 \left (2 c^2+8 c d+11 d^2\right )+\left (2 c^2+11 c d+29 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {\left (2 d^3 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {2 a-x^2}} \, dx,x,\sqrt {a-a \sec (e+f x)}\right )}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {(c-d) (c+d \sec (e+f x))^2 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {(c-d) \left (2 \left (2 c^2+8 c d+11 d^2\right )+\left (2 c^2+11 c d+29 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2}+\frac {\left (2 d^3 \tan (e+f x)\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt {a-a \sec (e+f x)}}{\sqrt {a+a \sec (e+f x)}}\right )}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}} \\ & = \frac {2 d^3 \arctan \left (\frac {\sqrt {a-a \sec (e+f x)}}{\sqrt {a+a \sec (e+f x)}}\right ) \tan (e+f x)}{a^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}+\frac {(c-d) (c+d \sec (e+f x))^2 \tan (e+f x)}{5 f (a+a \sec (e+f x))^3}+\frac {(c-d) \left (2 \left (2 c^2+8 c d+11 d^2\right )+\left (2 c^2+11 c d+29 d^2\right ) \sec (e+f x)\right ) \tan (e+f x)}{15 a f (a+a \sec (e+f x))^2} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(295\) vs. \(2(133)=266\).
Time = 2.59 (sec) , antiderivative size = 295, normalized size of antiderivative = 2.22 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {-240 d^3 \cos ^6\left (\frac {1}{2} (e+f x)\right ) \left (\log \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )\right )+(c-d) \cos \left (\frac {1}{2} (e+f x)\right ) \sec \left (\frac {e}{2}\right ) \left (5 \left (8 c^2+17 c d+29 d^2\right ) \sin \left (\frac {f x}{2}\right )-15 \left (2 c^2+5 c d+5 d^2\right ) \sin \left (e+\frac {f x}{2}\right )+20 c^2 \sin \left (e+\frac {3 f x}{2}\right )+65 c d \sin \left (e+\frac {3 f x}{2}\right )+95 d^2 \sin \left (e+\frac {3 f x}{2}\right )-15 c^2 \sin \left (2 e+\frac {3 f x}{2}\right )-15 c d \sin \left (2 e+\frac {3 f x}{2}\right )-15 d^2 \sin \left (2 e+\frac {3 f x}{2}\right )+7 c^2 \sin \left (2 e+\frac {5 f x}{2}\right )+16 c d \sin \left (2 e+\frac {5 f x}{2}\right )+22 d^2 \sin \left (2 e+\frac {5 f x}{2}\right )\right )}{30 a^3 f (1+\cos (e+f x))^3} \]
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Time = 0.69 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.88
method | result | size |
parallelrisch | \(\frac {-60 \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right ) d^{3}+60 \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right ) d^{3}+3 \left (c -d \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) \left (\left (c -d \right )^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{4}-\frac {10 \left (c +2 d \right ) \left (c -d \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}}{3}+5 c^{2}+20 c d +35 d^{2}\right )}{60 a^{3} f}\) | \(117\) |
derivativedivides | \(\frac {-\frac {2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c^{3}}{3}+2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c \,d^{2}+3 c^{2} d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+3 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c \,d^{2}-\frac {3 c^{2} d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}+\frac {3 c \,d^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}+c^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )-7 d^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+4 \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right ) d^{3}+\frac {c^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}-\frac {d^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}-\frac {4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} d^{3}}{3}-4 \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right ) d^{3}}{4 f \,a^{3}}\) | \(216\) |
default | \(\frac {-\frac {2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c^{3}}{3}+2 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} c \,d^{2}+3 c^{2} d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+3 \tan \left (\frac {f x}{2}+\frac {e}{2}\right ) c \,d^{2}-\frac {3 c^{2} d \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}+\frac {3 c \,d^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}+c^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )-7 d^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+4 \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right ) d^{3}+\frac {c^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}-\frac {d^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{5}-\frac {4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3} d^{3}}{3}-4 \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right ) d^{3}}{4 f \,a^{3}}\) | \(216\) |
risch | \(\frac {2 i \left (15 c^{3} {\mathrm e}^{4 i \left (f x +e \right )}-15 d^{3} {\mathrm e}^{4 i \left (f x +e \right )}+30 c^{3} {\mathrm e}^{3 i \left (f x +e \right )}+45 c^{2} d \,{\mathrm e}^{3 i \left (f x +e \right )}-75 d^{3} {\mathrm e}^{3 i \left (f x +e \right )}+40 c^{3} {\mathrm e}^{2 i \left (f x +e \right )}+45 c^{2} d \,{\mathrm e}^{2 i \left (f x +e \right )}+60 c \,d^{2} {\mathrm e}^{2 i \left (f x +e \right )}-145 d^{3} {\mathrm e}^{2 i \left (f x +e \right )}+20 c^{3} {\mathrm e}^{i \left (f x +e \right )}+45 c^{2} d \,{\mathrm e}^{i \left (f x +e \right )}+30 c \,d^{2} {\mathrm e}^{i \left (f x +e \right )}-95 d^{3} {\mathrm e}^{i \left (f x +e \right )}+7 c^{3}+9 c^{2} d +6 c \,d^{2}-22 d^{3}\right )}{15 f \,a^{3} \left ({\mathrm e}^{i \left (f x +e \right )}+1\right )^{5}}-\frac {d^{3} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-i\right )}{a^{3} f}+\frac {d^{3} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+i\right )}{a^{3} f}\) | \(281\) |
norman | \(\frac {\frac {\left (c^{3}-3 c^{2} d +3 c \,d^{2}-d^{3}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{11}}{20 a f}-\frac {\left (c^{3}+3 c^{2} d +3 c \,d^{2}-7 d^{3}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{4 a f}+\frac {3 \left (3 c^{3}+c^{2} d -c \,d^{2}-3 d^{3}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{7}}{10 a f}+\frac {\left (11 c^{3}+27 c^{2} d +21 c \,d^{2}-59 d^{3}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}{12 a f}-\frac {\left (13 c^{3}+21 c^{2} d +9 c \,d^{2}-43 d^{3}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{5}}{10 a f}-\frac {\left (19 c^{3}-27 c^{2} d -3 c \,d^{2}+11 d^{3}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{9}}{60 a f}}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1\right )^{3} a^{2}}+\frac {d^{3} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}{a^{3} f}-\frac {d^{3} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{a^{3} f}\) | \(312\) |
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Time = 0.27 (sec) , antiderivative size = 248, normalized size of antiderivative = 1.86 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {15 \, {\left (d^{3} \cos \left (f x + e\right )^{3} + 3 \, d^{3} \cos \left (f x + e\right )^{2} + 3 \, d^{3} \cos \left (f x + e\right ) + d^{3}\right )} \log \left (\sin \left (f x + e\right ) + 1\right ) - 15 \, {\left (d^{3} \cos \left (f x + e\right )^{3} + 3 \, d^{3} \cos \left (f x + e\right )^{2} + 3 \, d^{3} \cos \left (f x + e\right ) + d^{3}\right )} \log \left (-\sin \left (f x + e\right ) + 1\right ) + 2 \, {\left (2 \, c^{3} + 9 \, c^{2} d + 21 \, c d^{2} - 32 \, d^{3} + {\left (7 \, c^{3} + 9 \, c^{2} d + 6 \, c d^{2} - 22 \, d^{3}\right )} \cos \left (f x + e\right )^{2} + 3 \, {\left (2 \, c^{3} + 9 \, c^{2} d + 6 \, c d^{2} - 17 \, d^{3}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{30 \, {\left (a^{3} f \cos \left (f x + e\right )^{3} + 3 \, a^{3} f \cos \left (f x + e\right )^{2} + 3 \, a^{3} f \cos \left (f x + e\right ) + a^{3} f\right )}} \]
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\[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {\int \frac {c^{3} \sec {\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {d^{3} \sec ^{4}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {3 c d^{2} \sec ^{3}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx + \int \frac {3 c^{2} d \sec ^{2}{\left (e + f x \right )}}{\sec ^{3}{\left (e + f x \right )} + 3 \sec ^{2}{\left (e + f x \right )} + 3 \sec {\left (e + f x \right )} + 1}\, dx}{a^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 307 vs. \(2 (126) = 252\).
Time = 0.23 (sec) , antiderivative size = 307, normalized size of antiderivative = 2.31 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=-\frac {d^{3} {\left (\frac {\frac {105 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {20 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}}{a^{3}} - \frac {60 \, \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right )}{a^{3}} + \frac {60 \, \log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - 1\right )}{a^{3}}\right )} - \frac {3 \, c d^{2} {\left (\frac {15 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {10 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3}} - \frac {c^{3} {\left (\frac {15 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {10 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3}} - \frac {9 \, c^{2} d {\left (\frac {5 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {\sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}}\right )}}{a^{3}}}{60 \, f} \]
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Leaf count of result is larger than twice the leaf count of optimal. 259 vs. \(2 (126) = 252\).
Time = 0.37 (sec) , antiderivative size = 259, normalized size of antiderivative = 1.95 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {\frac {60 \, d^{3} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1 \right |}\right )}{a^{3}} - \frac {60 \, d^{3} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 1 \right |}\right )}{a^{3}} + \frac {3 \, a^{12} c^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 9 \, a^{12} c^{2} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} + 9 \, a^{12} c d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 3 \, a^{12} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 10 \, a^{12} c^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 30 \, a^{12} c d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 20 \, a^{12} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 15 \, a^{12} c^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 45 \, a^{12} c^{2} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 45 \, a^{12} c d^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 105 \, a^{12} d^{3} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}{a^{15}}}{60 \, f} \]
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Time = 13.52 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.11 \[ \int \frac {\sec (e+f x) (c+d \sec (e+f x))^3}{(a+a \sec (e+f x))^3} \, dx=\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (\frac {{\left (c-d\right )}^3}{4\,a^3}-\frac {3\,\left (c+d\right )\,{\left (c-d\right )}^2}{4\,a^3}+\frac {3\,{\left (c+d\right )}^2\,\left (c-d\right )}{4\,a^3}\right )}{f}+\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (\frac {{\left (c-d\right )}^3}{12\,a^3}-\frac {\left (c+d\right )\,{\left (c-d\right )}^2}{4\,a^3}\right )}{f}+\frac {2\,d^3\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )}{a^3\,f}+\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\left (c-d\right )}^3}{20\,a^3\,f} \]
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